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214344311132 = 2277655153969
BaseRepresentation
bin1100011110011111101…
…0101010000101011100
3202111021000122012011002
43013213322222011130
512002434120424012
6242245102245432
721325436404040
oct3074772520534
9674230565132
10214344311132
11829a2859496
123565b586878
131729c071a43
14a5351c4020
15589791a7c2
hex31e7eaa15c

214344311132 has 12 divisors (see below), whose sum is σ = 428688622320. Its totient is φ = 91861847616.

The previous prime is 214344311119. The next prime is 214344311161. The reversal of 214344311132 is 231113443412.

214344311132 is an admirable number.

It is a junction number, because it is equal to n+sod(n) for n = 214344311095 and 214344311104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3827576957 + ... + 3827577012.

It is an arithmetic number, because the mean of its divisors is an integer number (35724051860).

Almost surely, 2214344311132 is an apocalyptic number.

It is an amenable number.

214344311132 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

214344311132 is a wasteful number, since it uses less digits than its factorization.

214344311132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7655153980 (or 7655153978 counting only the distinct ones).

The product of its digits is 6912, while the sum is 29.

Adding to 214344311132 its reverse (231113443412), we get a palindrome (445457754544).

The spelling of 214344311132 in words is "two hundred fourteen billion, three hundred forty-four million, three hundred eleven thousand, one hundred thirty-two".

Divisors: 1 2 4 7 14 28 7655153969 15310307938 30620615876 53586077783 107172155566 214344311132