Base | Representation |
---|---|
bin | 111111111000010… |
… | …0110100000111111 |
3 | 12112101021101122202 |
4 | 1333300212200333 |
5 | 13342210301403 |
6 | 552405302115 |
7 | 104054666630 |
oct | 17760464077 |
9 | 5471241582 |
10 | 2143447103 |
11 | 9aaa13596 |
12 | 4b9a0493b |
13 | 2820c06c5 |
14 | 164959887 |
15 | c829a688 |
hex | 7fc2683f |
2143447103 has 4 divisors (see below), whose sum is σ = 2449653840. Its totient is φ = 1837240368.
The previous prime is 2143447093. The next prime is 2143447123. The reversal of 2143447103 is 3017443412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2143447103 - 210 = 2143446079 is a prime.
It is a super-3 number, since 3×21434471033 (a number of 29 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2143447123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153103358 + ... + 153103371.
It is an arithmetic number, because the mean of its divisors is an integer number (612413460).
Almost surely, 22143447103 is an apocalyptic number.
2143447103 is a deficient number, since it is larger than the sum of its proper divisors (306206737).
2143447103 is an equidigital number, since it uses as much as digits as its factorization.
2143447103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 306206736.
The product of its (nonzero) digits is 8064, while the sum is 29.
The square root of 2143447103 is about 46297.3768479382. The cubic root of 2143447103 is about 1289.3502933868.
The spelling of 2143447103 in words is "two billion, one hundred forty-three million, four hundred forty-seven thousand, one hundred three".
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