Base | Representation |
---|---|
bin | 11111001100010010111… |
… | …011010101011101111011 |
3 | 21120220202122010102020011 |
4 | 133030102323111131323 |
5 | 240104400043200034 |
6 | 4320414013242351 |
7 | 310602040201525 |
oct | 37142273253573 |
9 | 7526678112204 |
10 | 2143506225019 |
11 | 757068423755 |
12 | 2a7513a933b7 |
13 | 127193662213 |
14 | 75a63a1aa15 |
15 | 3ab5693a864 |
hex | 1f312ed577b |
2143506225019 has 2 divisors, whose sum is σ = 2143506225020. Its totient is φ = 2143506225018.
The previous prime is 2143506224969. The next prime is 2143506225059. The reversal of 2143506225019 is 9105226053412.
It is an a-pointer prime, because the next prime (2143506225059) can be obtained adding 2143506225019 to its sum of digits (40).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2143506225019 - 27 = 2143506224891 is a prime.
It is a super-3 number, since 3×21435062250193 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (2143506225059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1071753112509 + 1071753112510.
It is an arithmetic number, because the mean of its divisors is an integer number (1071753112510).
Almost surely, 22143506225019 is an apocalyptic number.
2143506225019 is a deficient number, since it is larger than the sum of its proper divisors (1).
2143506225019 is an equidigital number, since it uses as much as digits as its factorization.
2143506225019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 40.
The spelling of 2143506225019 in words is "two trillion, one hundred forty-three billion, five hundred six million, two hundred twenty-five thousand, nineteen".
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