Base | Representation |
---|---|
bin | 11111001100100001000… |
… | …111011011000110001111 |
3 | 21120221101020001121011212 |
4 | 133030201013123012033 |
5 | 240110342013243311 |
6 | 4320453355405035 |
7 | 310610660452355 |
oct | 37144107330617 |
9 | 7527336047155 |
10 | 2143744274831 |
11 | 75717a835035 |
12 | 2a757b75377b |
13 | 127200a7c4b3 |
14 | 75a874a57d5 |
15 | 3ab6c7adc8b |
hex | 1f3211db18f |
2143744274831 has 2 divisors, whose sum is σ = 2143744274832. Its totient is φ = 2143744274830.
The previous prime is 2143744274767. The next prime is 2143744274839. The reversal of 2143744274831 is 1384724473412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2143744274831 - 26 = 2143744274767 is a prime.
It is a super-2 number, since 2×21437442748312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2143744274831.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2143744274839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1071872137415 + 1071872137416.
It is an arithmetic number, because the mean of its divisors is an integer number (1071872137416).
Almost surely, 22143744274831 is an apocalyptic number.
2143744274831 is a deficient number, since it is larger than the sum of its proper divisors (1).
2143744274831 is an equidigital number, since it uses as much as digits as its factorization.
2143744274831 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3612672, while the sum is 50.
The spelling of 2143744274831 in words is "two trillion, one hundred forty-three billion, seven hundred forty-four million, two hundred seventy-four thousand, eight hundred thirty-one".
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