Base | Representation |
---|---|
bin | 1100011110101101010… |
… | …0001001010001011111 |
3 | 202111101222220202021111 |
4 | 3013223110021101133 |
5 | 12003043214333002 |
6 | 242254500242451 |
7 | 21330031120504 |
oct | 3075324112137 |
9 | 674358822244 |
10 | 214401324127 |
11 | 82a21a5a171 |
12 | 356766a0427 |
13 | 172aab14243 |
14 | a53c9c54ab |
15 | 589c92d3d7 |
hex | 31eb50945f |
214401324127 has 2 divisors, whose sum is σ = 214401324128. Its totient is φ = 214401324126.
The previous prime is 214401324119. The next prime is 214401324131. The reversal of 214401324127 is 721423104412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 214401324127 - 23 = 214401324119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214401324167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107200662063 + 107200662064.
It is an arithmetic number, because the mean of its divisors is an integer number (107200662064).
Almost surely, 2214401324127 is an apocalyptic number.
214401324127 is a deficient number, since it is larger than the sum of its proper divisors (1).
214401324127 is an equidigital number, since it uses as much as digits as its factorization.
214401324127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10752, while the sum is 31.
Adding to 214401324127 its reverse (721423104412), we get a palindrome (935824428539).
The spelling of 214401324127 in words is "two hundred fourteen billion, four hundred one million, three hundred twenty-four thousand, one hundred twenty-seven".
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