21440434404341 has 2 divisors, whose sum is σ = 21440434404342. Its totient is φ = 21440434404340.

The previous prime is 21440434404283. The next prime is 21440434404421. The reversal of 21440434404341 is 14340443404412.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11712335784241 + 9728098620100 = 3422329^2 + 3118990^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-21440434404341 is a prime.

It is a super-2 number, since 2×21440434404341² (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 21440434404295 and 21440434404304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21440434401341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10720217202170 + 10720217202171.

It is an arithmetic number, because the mean of its divisors is an integer number (10720217202171).

Almost surely, 2^{21440434404341} is an apocalyptic number.

It is an amenable number.

21440434404341 is a deficient number, since it is larger than the sum of its proper divisors (1).

21440434404341 is an equidigital number, since it uses as much as digits as its factorization.

21440434404341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 294912, while the sum is 38.

Adding to 21440434404341 its reverse (14340443404412), we get a palindrome (35780877808753).

The spelling of 21440434404341 in words is "twenty-one trillion, four hundred forty billion, four hundred thirty-four million, four hundred four thousand, three hundred forty-one".