Base | Representation |
---|---|
bin | 1001101111111111111010… |
… | …11110011111110001101101 |
3 | 2210220200111201220212112012 |
4 | 10313333331132133301231 |
5 | 10302240002201420321 |
6 | 113333333302251005 |
7 | 4342006644316022 |
oct | 467777536376155 |
9 | 83820451825465 |
10 | 21440434404461 |
11 | 69169232a7916 |
12 | 24a3372126a65 |
13 | bc6a93c69407 |
14 | 541a189d3549 |
15 | 272aacbda05b |
hex | 137ffd79fc6d |
21440434404461 has 2 divisors, whose sum is σ = 21440434404462. Its totient is φ = 21440434404460.
The previous prime is 21440434404421. The next prime is 21440434404491. The reversal of 21440434404461 is 16440443404412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18247848062500 + 3192586341961 = 4271750^2 + 1786781^2 .
It is a cyclic number.
It is not a de Polignac number, because 21440434404461 - 218 = 21440434142317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21440434404421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10720217202230 + 10720217202231.
It is an arithmetic number, because the mean of its divisors is an integer number (10720217202231).
Almost surely, 221440434404461 is an apocalyptic number.
It is an amenable number.
21440434404461 is a deficient number, since it is larger than the sum of its proper divisors (1).
21440434404461 is an equidigital number, since it uses as much as digits as its factorization.
21440434404461 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 589824, while the sum is 41.
Adding to 21440434404461 its reverse (16440443404412), we get a palindrome (37880877808873).
The spelling of 21440434404461 in words is "twenty-one trillion, four hundred forty billion, four hundred thirty-four million, four hundred four thousand, four hundred sixty-one".
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