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2144113035 = 351153123973
BaseRepresentation
bin111111111001100…
…1001000110001011
312112102112020010220
41333303021012023
513342343104120
6552431441123
7104063442261
oct17763110613
95472466126
102144113035
11a00328949
124ba0861a3
1328229484c
14164a90431
15c837cb40
hex7fcc918b

2144113035 has 16 divisors (see below), whose sum is σ = 3433583904. Its totient is φ = 1142525952.

The previous prime is 2144113019. The next prime is 2144113043. The reversal of 2144113035 is 5303114412.

It is a happy number.

It is not a de Polignac number, because 2144113035 - 24 = 2144113019 is a prime.

It is a super-2 number, since 2×21441130352 = 9194441413713822450, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2144112996 and 2144113014.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44692 + ... + 79281.

It is an arithmetic number, because the mean of its divisors is an integer number (214598994).

Almost surely, 22144113035 is an apocalyptic number.

2144113035 is a deficient number, since it is larger than the sum of its proper divisors (1289470869).

2144113035 is a wasteful number, since it uses less digits than its factorization.

2144113035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 125134.

The product of its (nonzero) digits is 1440, while the sum is 24.

The square root of 2144113035 is about 46304.5681871670. The cubic root of 2144113035 is about 1289.4838058513.

Adding to 2144113035 its reverse (5303114412), we get a palindrome (7447227447).

The spelling of 2144113035 in words is "two billion, one hundred forty-four million, one hundred thirteen thousand, thirty-five".

Divisors: 1 3 5 15 1153 3459 5765 17295 123973 371919 619865 1859595 142940869 428822607 714704345 2144113035