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214411311403 is a prime number
BaseRepresentation
bin1100011110101111101…
…0001111100100101011
3202111102200201011020121
43013223322033210223
512003103243431103
6242255454304111
721330212035102
oct3075372174453
9674380634217
10214411311403
1182a27660813
1235679ab8037
13172acc00083
14a540065039
15589d7526bd
hex31ebe8f92b

214411311403 has 2 divisors, whose sum is σ = 214411311404. Its totient is φ = 214411311402.

The previous prime is 214411311383. The next prime is 214411311437. The reversal of 214411311403 is 304113114412.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 214411311403 - 221 = 214409214251 is a prime.

It is not a weakly prime, because it can be changed into another prime (214411311203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107205655701 + 107205655702.

It is an arithmetic number, because the mean of its divisors is an integer number (107205655702).

Almost surely, 2214411311403 is an apocalyptic number.

214411311403 is a deficient number, since it is larger than the sum of its proper divisors (1).

214411311403 is an equidigital number, since it uses as much as digits as its factorization.

214411311403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 214411311403 its reverse (304113114412), we get a palindrome (518524425815).

The spelling of 214411311403 in words is "two hundred fourteen billion, four hundred eleven million, three hundred eleven thousand, four hundred three".