Base | Representation |
---|---|
bin | 11111001100111001111… |
… | …011101000011001001111 |
3 | 21120222110020110211002212 |
4 | 133030321323220121033 |
5 | 240112220104121332 |
6 | 4321002551141035 |
7 | 310624204335161 |
oct | 37147173503117 |
9 | 7528406424085 |
10 | 2144160613967 |
11 | 75737384a869 |
12 | 2a767707477b |
13 | 1272690c1b08 |
14 | 75ac68c0931 |
15 | 3ab940ed8b2 |
hex | 1f339ee864f |
2144160613967 has 4 divisors (see below), whose sum is σ = 2145863681640. Its totient is φ = 2142457546296.
The previous prime is 2144160613949. The next prime is 2144160613993. The reversal of 2144160613967 is 7693160614412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2144160613967 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2144160613367) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 851531948 + ... + 851534465.
It is an arithmetic number, because the mean of its divisors is an integer number (536465920410).
Almost surely, 22144160613967 is an apocalyptic number.
2144160613967 is a deficient number, since it is larger than the sum of its proper divisors (1703067673).
2144160613967 is a wasteful number, since it uses less digits than its factorization.
2144160613967 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1703067672.
The product of its (nonzero) digits is 1306368, while the sum is 50.
The spelling of 2144160613967 in words is "two trillion, one hundred forty-four billion, one hundred sixty million, six hundred thirteen thousand, nine hundred sixty-seven".
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