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21442314433 is a prime number
BaseRepresentation
bin10011111110000011…
…111100000011000001
32001100100111102200211
4103332003330003001
5322403213030213
613503411114121
71356234444151
oct237603740301
961310442624
1021442314433
11910369a221
1241a4ba2941
132039450527
141075a90761
158576bd53d
hex4fe0fc0c1

21442314433 has 2 divisors, whose sum is σ = 21442314434. Its totient is φ = 21442314432.

The previous prime is 21442314427. The next prime is 21442314451. The reversal of 21442314433 is 33441324412.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19912878769 + 1529435664 = 141113^2 + 39108^2 .

It is a cyclic number.

It is not a de Polignac number, because 21442314433 - 25 = 21442314401 is a prime.

It is a super-2 number, since 2×214423144332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21442314395 and 21442314404.

It is not a weakly prime, because it can be changed into another prime (21442314403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10721157216 + 10721157217.

It is an arithmetic number, because the mean of its divisors is an integer number (10721157217).

Almost surely, 221442314433 is an apocalyptic number.

It is an amenable number.

21442314433 is a deficient number, since it is larger than the sum of its proper divisors (1).

21442314433 is an equidigital number, since it uses as much as digits as its factorization.

21442314433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 27648, while the sum is 31.

Adding to 21442314433 its reverse (33441324412), we get a palindrome (54883638845).

The spelling of 21442314433 in words is "twenty-one billion, four hundred forty-two million, three hundred fourteen thousand, four hundred thirty-three".