Base | Representation |
---|---|
bin | 11111001100111111100… |
… | …011101100011011011011 |
3 | 21120222200211002020121012 |
4 | 133030333203230123123 |
5 | 240112413240033311 |
6 | 4321020202204135 |
7 | 310626431536001 |
oct | 37147743543333 |
9 | 7528624066535 |
10 | 2144255002331 |
11 | 757412059182 |
12 | 2a76a27b364b |
13 | 12728281c310 |
14 | 75ad5250a71 |
15 | 3ab9c54578b |
hex | 1f33f8ec6db |
2144255002331 has 4 divisors (see below), whose sum is σ = 2309197694832. Its totient is φ = 1979312309832.
The previous prime is 2144255002319. The next prime is 2144255002361. The reversal of 2144255002331 is 1332005524412.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 2144255002331 - 210 = 2144255001307 is a prime.
It is a super-2 number, since 2×21442550023312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2144255002361) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82471346231 + ... + 82471346256.
It is an arithmetic number, because the mean of its divisors is an integer number (577299423708).
Almost surely, 22144255002331 is an apocalyptic number.
2144255002331 is a deficient number, since it is larger than the sum of its proper divisors (164942692501).
2144255002331 is a wasteful number, since it uses less digits than its factorization.
2144255002331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 164942692500.
The product of its (nonzero) digits is 28800, while the sum is 32.
The spelling of 2144255002331 in words is "two trillion, one hundred forty-four billion, two hundred fifty-five million, two thousand, three hundred thirty-one".
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