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2144340115 = 5428868023
BaseRepresentation
bin111111111010000…
…0000100010010011
312112102221202122021
41333310000202103
513342422340430
6552440352311
7104065406311
oct17764004223
95472852567
102144340115
11a00473515
124ba175697
13282344008
14164b0d0b1
15c83c507a
hex7fd00893

2144340115 has 4 divisors (see below), whose sum is σ = 2573208144. Its totient is φ = 1715472088.

The previous prime is 2144340097. The next prime is 2144340119. The reversal of 2144340115 is 5110434412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2144340115 - 213 = 2144331923 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2144340115.

It is not an unprimeable number, because it can be changed into a prime (2144340119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214434007 + ... + 214434016.

It is an arithmetic number, because the mean of its divisors is an integer number (643302036).

Almost surely, 22144340115 is an apocalyptic number.

2144340115 is a deficient number, since it is larger than the sum of its proper divisors (428868029).

2144340115 is an equidigital number, since it uses as much as digits as its factorization.

2144340115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 428868028.

The product of its (nonzero) digits is 1920, while the sum is 25.

The square root of 2144340115 is about 46307.0201481374. The cubic root of 2144340115 is about 1289.5293267172.

Adding to 2144340115 its reverse (5110434412), we get a palindrome (7254774527).

The spelling of 2144340115 in words is "two billion, one hundred forty-four million, three hundred forty thousand, one hundred fifteen".

Divisors: 1 5 428868023 2144340115