Base | Representation |
---|---|
bin | 110000110000100001010010… |
… | …100011111011011101101111 |
3 | 1001010021022110000011201011202 |
4 | 300300201102203323131233 |
5 | 211101343132122230012 |
6 | 2040024340020040115 |
7 | 63111546541543532 |
oct | 6060412243733557 |
9 | 1033238400151152 |
10 | 214440512305007 |
11 | 6236678a81a73a |
12 | 2007401183303b |
13 | 9286865aa6571 |
14 | 3ad4d9489ca19 |
15 | 19bd153316cc2 |
hex | c308528fb76f |
214440512305007 has 2 divisors, whose sum is σ = 214440512305008. Its totient is φ = 214440512305006.
The previous prime is 214440512304973. The next prime is 214440512305027. The reversal of 214440512305007 is 700503215044412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 214440512305007 - 214 = 214440512288623 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214440512305027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107220256152503 + 107220256152504.
It is an arithmetic number, because the mean of its divisors is an integer number (107220256152504).
Almost surely, 2214440512305007 is an apocalyptic number.
214440512305007 is a deficient number, since it is larger than the sum of its proper divisors (1).
214440512305007 is an equidigital number, since it uses as much as digits as its factorization.
214440512305007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 134400, while the sum is 38.
Adding to 214440512305007 its reverse (700503215044412), we get a palindrome (914943727349419).
The spelling of 214440512305007 in words is "two hundred fourteen trillion, four hundred forty billion, five hundred twelve million, three hundred five thousand, seven".
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