2144431099981 has 2 divisors, whose sum is σ = 2144431099982. Its totient is φ = 2144431099980.

The previous prime is 2144431099973. The next prime is 2144431100047. The reversal of 2144431099981 is 1899901344412.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1139406804900 + 1005024295081 = 1067430^2 + 1002509^2 .

It is a cyclic number.

It is not a de Polignac number, because 2144431099981 - 2³ = 2144431099973 is a prime.

It is a super-2 number, since 2×2144431099981² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2144431099781) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1072215549990 + 1072215549991.

It is an arithmetic number, because the mean of its divisors is an integer number (1072215549991).

Almost surely, 2^{2144431099981} is an apocalyptic number.

It is an amenable number.

2144431099981 is a deficient number, since it is larger than the sum of its proper divisors (1).

2144431099981 is an equidigital number, since it uses as much as digits as its factorization.

2144431099981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2239488, while the sum is 55.

The spelling of 2144431099981 in words is "two trillion, one hundred forty-four billion, four hundred thirty-one million, ninety-nine thousand, nine hundred eighty-one".