Base | Representation |
---|---|
bin | 11111001101101100000… |
… | …110110101110001011001 |
3 | 21121001121220110122111012 |
4 | 133031230012311301121 |
5 | 240120431104210040 |
6 | 4321222301543305 |
7 | 310654105452164 |
oct | 37155406656131 |
9 | 7531556418435 |
10 | 2145002413145 |
11 | 757765a3aa69 |
12 | 2a7870b74b35 |
13 | 12737161b437 |
14 | 75b6660aadb |
15 | 3abe2e80865 |
hex | 1f36c1b5c59 |
2145002413145 has 16 divisors (see below), whose sum is σ = 2583431519760. Its totient is φ = 1709717452800.
The previous prime is 2145002413139. The next prime is 2145002413153. The reversal of 2145002413145 is 5413142005412.
It can be written as a sum of positive squares in 8 ways, for example, as 34199104 + 2144968214041 = 5848^2 + 1464571^2 .
It is a de Polignac number, because none of the positive numbers 2k-2145002413145 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14381855 + ... + 14530235.
It is an arithmetic number, because the mean of its divisors is an integer number (161464469985).
Almost surely, 22145002413145 is an apocalyptic number.
It is an amenable number.
2145002413145 is a deficient number, since it is larger than the sum of its proper divisors (438429106615).
2145002413145 is a wasteful number, since it uses less digits than its factorization.
2145002413145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 158956.
The product of its (nonzero) digits is 19200, while the sum is 32.
Adding to 2145002413145 its reverse (5413142005412), we get a palindrome (7558144418557).
The spelling of 2145002413145 in words is "two trillion, one hundred forty-five billion, two million, four hundred thirteen thousand, one hundred forty-five".
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