Base | Representation |
---|---|
bin | 1100011111000110000… |
… | …1100100111000100111 |
3 | 202111200020221212012221 |
4 | 3013301201210320213 |
5 | 12003301402232031 |
6 | 242313101253211 |
7 | 21332434510636 |
oct | 3076141447047 |
9 | 674606855187 |
10 | 214505508391 |
11 | 82a75849369 |
12 | 356a5564207 |
13 | 172c6591435 |
14 | a54c78551d |
15 | 58a6b5ca11 |
hex | 31f1864e27 |
214505508391 has 2 divisors, whose sum is σ = 214505508392. Its totient is φ = 214505508390.
The previous prime is 214505508367. The next prime is 214505508403. The reversal of 214505508391 is 193805505412.
214505508391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-214505508391 is a prime.
It is a super-2 number, since 2×2145055083912 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214505508341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107252754195 + 107252754196.
It is an arithmetic number, because the mean of its divisors is an integer number (107252754196).
Almost surely, 2214505508391 is an apocalyptic number.
214505508391 is a deficient number, since it is larger than the sum of its proper divisors (1).
214505508391 is an equidigital number, since it uses as much as digits as its factorization.
214505508391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216000, while the sum is 43.
The spelling of 214505508391 in words is "two hundred fourteen billion, five hundred five million, five hundred eight thousand, three hundred ninety-one".
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