Base | Representation |
---|---|
bin | 11111001101110111111… |
… | …100100110001011000011 |
3 | 21121002010202020200001211 |
4 | 133031313330212023003 |
5 | 240121332432220103 |
6 | 4321254115310551 |
7 | 310662040050211 |
oct | 37156774461303 |
9 | 7532122220054 |
10 | 2145201054403 |
11 | 7578580850a0 |
12 | 2a79075ab457 |
13 | 1273a381b144 |
14 | 75b84b57cb1 |
15 | 3ac0561c36d |
hex | 1f377f262c3 |
2145201054403 has 32 divisors (see below), whose sum is σ = 2533940527104. Its totient is φ = 1795765620000.
The previous prime is 2145201054371. The next prime is 2145201054413. The reversal of 2145201054403 is 3044501025412.
It is not a de Polignac number, because 2145201054403 - 25 = 2145201054371 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2145201054413) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 781998 + ... + 2214028.
It is an arithmetic number, because the mean of its divisors is an integer number (79185641472).
Almost surely, 22145201054403 is an apocalyptic number.
2145201054403 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
2145201054403 is a deficient number, since it is larger than the sum of its proper divisors (388739472701).
2145201054403 is a wasteful number, since it uses less digits than its factorization.
2145201054403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1432287.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 2145201054403 its reverse (3044501025412), we get a palindrome (5189702079815).
The spelling of 2145201054403 in words is "two trillion, one hundred forty-five billion, two hundred one million, fifty-four thousand, four hundred three".
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