Base | Representation |
---|---|
bin | 11111001101111000101… |
… | …010101000101101001001 |
3 | 21121002011120221211121202 |
4 | 133031320222220231021 |
5 | 240121344024422101 |
6 | 4321255230113545 |
7 | 310662244454615 |
oct | 37157052505511 |
9 | 7532146854552 |
10 | 2145213123401 |
11 | 757863978777 |
12 | 2a790b64b8b5 |
13 | 1273a618566a |
14 | 75b865ba345 |
15 | 3ac0670336b |
hex | 1f378aa8b49 |
2145213123401 has 2 divisors, whose sum is σ = 2145213123402. Its totient is φ = 2145213123400.
The previous prime is 2145213123343. The next prime is 2145213123407. The reversal of 2145213123401 is 1043213125412.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1667868931600 + 477344191801 = 1291460^2 + 690901^2 .
It is a cyclic number.
It is not a de Polignac number, because 2145213123401 - 218 = 2145212861257 is a prime.
It is not a weakly prime, because it can be changed into another prime (2145213123407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1072606561700 + 1072606561701.
It is an arithmetic number, because the mean of its divisors is an integer number (1072606561701).
Almost surely, 22145213123401 is an apocalyptic number.
It is an amenable number.
2145213123401 is a deficient number, since it is larger than the sum of its proper divisors (1).
2145213123401 is an equidigital number, since it uses as much as digits as its factorization.
2145213123401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 2145213123401 its reverse (1043213125412), we get a palindrome (3188426248813).
The spelling of 2145213123401 in words is "two trillion, one hundred forty-five billion, two hundred thirteen million, one hundred twenty-three thousand, four hundred one".
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