Base | Representation |
---|---|
bin | 11111001110001011101… |
… | …000000101110101101011 |
3 | 21121002222202111222210022 |
4 | 133032023220011311223 |
5 | 240123021443122103 |
6 | 4321350552111055 |
7 | 311003156331101 |
oct | 37161350056553 |
9 | 7532882458708 |
10 | 2145531223403 |
11 | 757a07494a37 |
12 | 2a799a09548b |
13 | 12742704cb09 |
14 | 75bb6941c71 |
15 | 3ac245da138 |
hex | 1f38ba05d6b |
2145531223403 has 4 divisors (see below), whose sum is σ = 2145534632928. Its totient is φ = 2145527813880.
The previous prime is 2145531223397. The next prime is 2145531223457. The reversal of 2145531223403 is 3043221355412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2145531223403 - 210 = 2145531222379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2145531243403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 455876 + ... + 2121057.
It is an arithmetic number, because the mean of its divisors is an integer number (536383658232).
Almost surely, 22145531223403 is an apocalyptic number.
2145531223403 is a deficient number, since it is larger than the sum of its proper divisors (3409525).
2145531223403 is an equidigital number, since it uses as much as digits as its factorization.
2145531223403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3409524.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 2145531223403 its reverse (3043221355412), we get a palindrome (5188752578815).
The spelling of 2145531223403 in words is "two trillion, one hundred forty-five billion, five hundred thirty-one million, two hundred twenty-three thousand, four hundred three".
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