Base | Representation |
---|---|
bin | 11111001111110011110… |
… | …111010110010011000111 |
3 | 21121021111122020202121102 |
4 | 133033303313112103013 |
5 | 240140112143202242 |
6 | 4322240303410315 |
7 | 311064413206004 |
oct | 37176367262307 |
9 | 7537448222542 |
10 | 2147280053447 |
11 | 758724679921 |
12 | 2a81a78b399b |
13 | 1276454650a9 |
14 | 75d00cd88ab |
15 | 3acc7dd6e32 |
hex | 1f3f3dd64c7 |
2147280053447 has 4 divisors (see below), whose sum is σ = 2197216798920. Its totient is φ = 2097343307976.
The previous prime is 2147280053357. The next prime is 2147280053461. The reversal of 2147280053447 is 7443500827412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2147280053447 - 222 = 2147275859143 is a prime.
It is a super-2 number, since 2×21472800534472 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2147280053497) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24968372672 + ... + 24968372757.
It is an arithmetic number, because the mean of its divisors is an integer number (549304199730).
Almost surely, 22147280053447 is an apocalyptic number.
2147280053447 is a deficient number, since it is larger than the sum of its proper divisors (49936745473).
2147280053447 is an equidigital number, since it uses as much as digits as its factorization.
2147280053447 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49936745472.
The product of its (nonzero) digits is 1505280, while the sum is 47.
The spelling of 2147280053447 in words is "two trillion, one hundred forty-seven billion, two hundred eighty million, fifty-three thousand, four hundred forty-seven".
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