Base | Representation |
---|---|
bin | 11111010000000011111… |
… | …101101000111111000111 |
3 | 21121022012110110111101112 |
4 | 133100003331220333013 |
5 | 240141140313411221 |
6 | 4322323152315235 |
7 | 311104202662304 |
oct | 37200375507707 |
9 | 7538173414345 |
10 | 2147550138311 |
11 | 758853080656 |
12 | 2a8262242b1b |
13 | 1276893ba716 |
14 | 75d28b220ab |
15 | 3ace198715b |
hex | 1f403f68fc7 |
2147550138311 has 2 divisors, whose sum is σ = 2147550138312. Its totient is φ = 2147550138310.
The previous prime is 2147550138269. The next prime is 2147550138361. The reversal of 2147550138311 is 1138310557412.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2147550138311 is a prime.
It is a super-2 number, since 2×21475501383112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2147550138361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1073775069155 + 1073775069156.
It is an arithmetic number, because the mean of its divisors is an integer number (1073775069156).
Almost surely, 22147550138311 is an apocalyptic number.
2147550138311 is a deficient number, since it is larger than the sum of its proper divisors (1).
2147550138311 is an equidigital number, since it uses as much as digits as its factorization.
2147550138311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 41.
The spelling of 2147550138311 in words is "two trillion, one hundred forty-seven billion, five hundred fifty million, one hundred thirty-eight thousand, three hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •