Base | Representation |
---|---|
bin | 110000110101111010110001… |
… | …000010111011000001001011 |
3 | 1001011120202221022111121101002 |
4 | 300311322301002323001023 |
5 | 211123432334424103103 |
6 | 2040511005144445215 |
7 | 63150421226634011 |
oct | 6065726102730113 |
9 | 1034522838447332 |
10 | 214811464675403 |
11 | 6249a03775aa82 |
12 | 20113a98a7980b |
13 | 92b283245149b |
14 | 3b08d04cc68b1 |
15 | 19c7b14a0a488 |
hex | c35eb10bb04b |
214811464675403 has 2 divisors, whose sum is σ = 214811464675404. Its totient is φ = 214811464675402.
The previous prime is 214811464675399. The next prime is 214811464675501. The reversal of 214811464675403 is 304576464118412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 214811464675403 - 22 = 214811464675399 is a prime.
It is a super-2 number, since 2×2148114646754032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (214811464975403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107405732337701 + 107405732337702.
It is an arithmetic number, because the mean of its divisors is an integer number (107405732337702).
Almost surely, 2214811464675403 is an apocalyptic number.
214811464675403 is a deficient number, since it is larger than the sum of its proper divisors (1).
214811464675403 is an equidigital number, since it uses as much as digits as its factorization.
214811464675403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15482880, while the sum is 56.
The spelling of 214811464675403 in words is "two hundred fourteen trillion, eight hundred eleven billion, four hundred sixty-four million, six hundred seventy-five thousand, four hundred three".
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