Base | Representation |
---|---|
bin | 1100100000011010010… |
… | …1010101111001011111 |
3 | 202112120212202210200101 |
4 | 3020012211111321133 |
5 | 12010012324121434 |
6 | 242412122041531 |
7 | 21344254545352 |
oct | 3100645257137 |
9 | 675525683611 |
10 | 214858817119 |
11 | 83137223451 |
12 | 357839492a7 |
13 | 1735183565b |
14 | a583674299 |
15 | 58c7b9bb14 |
hex | 3206955e5f |
214858817119 has 2 divisors, whose sum is σ = 214858817120. Its totient is φ = 214858817118.
The previous prime is 214858817087. The next prime is 214858817137. The reversal of 214858817119 is 911718858412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 214858817119 - 25 = 214858817087 is a prime.
It is a super-2 number, since 2×2148588171192 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 214858817119.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214858817149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107429408559 + 107429408560.
It is an arithmetic number, because the mean of its divisors is an integer number (107429408560).
Almost surely, 2214858817119 is an apocalyptic number.
214858817119 is a deficient number, since it is larger than the sum of its proper divisors (1).
214858817119 is an equidigital number, since it uses as much as digits as its factorization.
214858817119 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1290240, while the sum is 55.
The spelling of 214858817119 in words is "two hundred fourteen billion, eight hundred fifty-eight million, eight hundred seventeen thousand, one hundred nineteen".
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