Base | Representation |
---|---|
bin | 11111010001100011011… |
… | …000101011111100010111 |
3 | 21121110100000212221100022 |
4 | 133101203120223330113 |
5 | 240202430133020311 |
6 | 4323150101535355 |
7 | 311161652425532 |
oct | 37214330537427 |
9 | 7543300787308 |
10 | 2149151063831 |
11 | 7594a48246a2 |
12 | 2a862a41455b |
13 | 127882c88825 |
14 | 7603b5b7a19 |
15 | 3ad872ba5db |
hex | 1f46362bf17 |
2149151063831 has 2 divisors, whose sum is σ = 2149151063832. Its totient is φ = 2149151063830.
The previous prime is 2149151063809. The next prime is 2149151063867. The reversal of 2149151063831 is 1383601519412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2149151063831 - 218 = 2149150801687 is a prime.
It is a super-2 number, since 2×21491510638312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2149151063431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1074575531915 + 1074575531916.
It is an arithmetic number, because the mean of its divisors is an integer number (1074575531916).
Almost surely, 22149151063831 is an apocalyptic number.
2149151063831 is a deficient number, since it is larger than the sum of its proper divisors (1).
2149151063831 is an equidigital number, since it uses as much as digits as its factorization.
2149151063831 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 44.
The spelling of 2149151063831 in words is "two trillion, one hundred forty-nine billion, one hundred fifty-one million, sixty-three thousand, eight hundred thirty-one".
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