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2149271286047 is a prime number
BaseRepresentation
bin11111010001101010100…
…011010011000100011111
321121110122102002212012222
4133101222203103010133
5240203201422123142
64323210034415555
7311164642333604
oct37215243230437
97543572085188
102149271286047
117595566783a6
122a86627315bb
131278a1b5c932
147604d5506ab
153ad92b16bd2
hex1f46a8d311f

2149271286047 has 2 divisors, whose sum is σ = 2149271286048. Its totient is φ = 2149271286046.

The previous prime is 2149271285989. The next prime is 2149271286077. The reversal of 2149271286047 is 7406821729412.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2149271286047 - 212 = 2149271281951 is a prime.

It is a super-2 number, since 2×21492712860472 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2149271286047.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2149271286077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1074635643023 + 1074635643024.

It is an arithmetic number, because the mean of its divisors is an integer number (1074635643024).

Almost surely, 22149271286047 is an apocalyptic number.

2149271286047 is a deficient number, since it is larger than the sum of its proper divisors (1).

2149271286047 is an equidigital number, since it uses as much as digits as its factorization.

2149271286047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2709504, while the sum is 53.

The spelling of 2149271286047 in words is "two trillion, one hundred forty-nine billion, two hundred seventy-one million, two hundred eighty-six thousand, forty-seven".