Base | Representation |
---|---|
bin | 1001110001101111110011… |
… | …10110100110000101010111 |
3 | 2211010102120000212120022211 |
4 | 10320313321312212011113 |
5 | 10304231012301430111 |
6 | 113421110024134251 |
7 | 4346234340264505 |
oct | 470677166460527 |
9 | 84112500776284 |
10 | 21500503155031 |
11 | 693a34857222a |
12 | 24b2b37007387 |
13 | bcc647a184c4 |
14 | 5448b6661675 |
15 | 2744264bd521 |
hex | 138df9da6157 |
21500503155031 has 2 divisors, whose sum is σ = 21500503155032. Its totient is φ = 21500503155030.
The previous prime is 21500503155011. The next prime is 21500503155041. The reversal of 21500503155031 is 13055130500512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21500503155031 - 217 = 21500503023959 is a prime.
It is a super-2 number, since 2×215005031550312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21500503154984 and 21500503155002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21500503155011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10750251577515 + 10750251577516.
It is an arithmetic number, because the mean of its divisors is an integer number (10750251577516).
Almost surely, 221500503155031 is an apocalyptic number.
21500503155031 is a deficient number, since it is larger than the sum of its proper divisors (1).
21500503155031 is an equidigital number, since it uses as much as digits as its factorization.
21500503155031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11250, while the sum is 31.
Adding to 21500503155031 its reverse (13055130500512), we get a palindrome (34555633655543).
The spelling of 21500503155031 in words is "twenty-one trillion, five hundred billion, five hundred three million, one hundred fifty-five thousand, thirty-one".
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