Base | Representation |
---|---|
bin | 1100100000111111001… |
… | …1000010111011111101 |
3 | 202112222122122122120201 |
4 | 3020033303002323331 |
5 | 12010321412420123 |
6 | 242435323243501 |
7 | 21351142532233 |
oct | 3101763027375 |
9 | 675878578521 |
10 | 215013404413 |
11 | 83206509145 |
12 | 35807679591 |
13 | 1737787c522 |
14 | a599dd4953 |
15 | 58d65355ad |
hex | 320fcc2efd |
215013404413 has 4 divisors (see below), whose sum is σ = 215014502560. Its totient is φ = 215012306268.
The previous prime is 215013404407. The next prime is 215013404509. The reversal of 215013404413 is 314404310512.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-215013404413 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (215013404513) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166545 + ... + 676582.
It is an arithmetic number, because the mean of its divisors is an integer number (53753625640).
Almost surely, 2215013404413 is an apocalyptic number.
It is an amenable number.
215013404413 is a deficient number, since it is larger than the sum of its proper divisors (1098147).
215013404413 is an equidigital number, since it uses as much as digits as its factorization.
215013404413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1098146.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 215013404413 its reverse (314404310512), we get a palindrome (529417714925).
The spelling of 215013404413 in words is "two hundred fifteen billion, thirteen million, four hundred four thousand, four hundred thirteen".
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