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21501514131371 is a prime number
BaseRepresentation
bin1001110001110001101100…
…00111001010011110101011
32211010112011111012111010222
410320320312013022132223
510304240100104200441
6113421354221000255
74346301364402421
oct470706607123653
984115144174128
1021501514131371
11693a81720276a
1224b31796b308b
13bcc7792c9761
14544970a29111
1527448511bd4b
hex138e361ca7ab

21501514131371 has 2 divisors, whose sum is σ = 21501514131372. Its totient is φ = 21501514131370.

The previous prime is 21501514131341. The next prime is 21501514131373. The reversal of 21501514131371 is 17313141510512.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21501514131371 - 214 = 21501514114987 is a prime.

Together with 21501514131373, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (21501514131373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10750757065685 + 10750757065686.

It is an arithmetic number, because the mean of its divisors is an integer number (10750757065686).

Almost surely, 221501514131371 is an apocalyptic number.

21501514131371 is a deficient number, since it is larger than the sum of its proper divisors (1).

21501514131371 is an equidigital number, since it uses as much as digits as its factorization.

21501514131371 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12600, while the sum is 35.

Adding to 21501514131371 its reverse (17313141510512), we get a palindrome (38814655641883).

The spelling of 21501514131371 in words is "twenty-one trillion, five hundred one billion, five hundred fourteen million, one hundred thirty-one thousand, three hundred seventy-one".