Base | Representation |
---|---|
bin | 1100100001000011001… |
… | …1010001011110101101 |
3 | 202120000211100001022022 |
4 | 3020100303101132231 |
5 | 12010340220204242 |
6 | 242441124155525 |
7 | 21351435615122 |
oct | 3102063213655 |
9 | 676024301268 |
10 | 215030241197 |
11 | 83214a68942 |
12 | 35811238ba5 |
13 | 1737b1c5c15 |
14 | a59c338749 |
15 | 58d7c5e0d2 |
hex | 3210cd17ad |
215030241197 has 2 divisors, whose sum is σ = 215030241198. Its totient is φ = 215030241196.
The previous prime is 215030241113. The next prime is 215030241253. The reversal of 215030241197 is 791142030512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 199581988516 + 15448252681 = 446746^2 + 124291^2 .
It is a cyclic number.
It is not a de Polignac number, because 215030241197 - 230 = 213956499373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (215030244197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107515120598 + 107515120599.
It is an arithmetic number, because the mean of its divisors is an integer number (107515120599).
Almost surely, 2215030241197 is an apocalyptic number.
It is an amenable number.
215030241197 is a deficient number, since it is larger than the sum of its proper divisors (1).
215030241197 is an equidigital number, since it uses as much as digits as its factorization.
215030241197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 35.
The spelling of 215030241197 in words is "two hundred fifteen billion, thirty million, two hundred forty-one thousand, one hundred ninety-seven".
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