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215042545114421 is a prime number
BaseRepresentation
bin110000111001010001111110…
…100000110101110100110101
31001012101212101201010011221112
4300321101332200311310311
5211141224113022130141
62041205103104324405
763203211510152603
oct6071217640656465
91035355351104845
10215042545114421
116257903862a012
1220150829313705
1392cb56a927a7b
143b16186adc873
1519cdb3b8787eb
hexc3947e835d35

215042545114421 has 2 divisors, whose sum is σ = 215042545114422. Its totient is φ = 215042545114420.

The previous prime is 215042545114417. The next prime is 215042545114433. The reversal of 215042545114421 is 124411545240512.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 159295042833796 + 55747502280625 = 12621214^2 + 7466425^2 .

It is a cyclic number.

It is not a de Polignac number, because 215042545114421 - 22 = 215042545114417 is a prime.

It is a super-3 number, since 3×2150425451144213 (a number of 44 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (215042545114451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107521272557210 + 107521272557211.

It is an arithmetic number, because the mean of its divisors is an integer number (107521272557211).

Almost surely, 2215042545114421 is an apocalyptic number.

It is an amenable number.

215042545114421 is a deficient number, since it is larger than the sum of its proper divisors (1).

215042545114421 is an equidigital number, since it uses as much as digits as its factorization.

215042545114421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 256000, while the sum is 41.

The spelling of 215042545114421 in words is "two hundred fifteen trillion, forty-two billion, five hundred forty-five million, one hundred fourteen thousand, four hundred twenty-one".