Base | Representation |
---|---|
bin | 1100100001000110100… |
… | …0010011111111100011 |
3 | 202120001210111102220112 |
4 | 3020101220103333203 |
5 | 12010402300120443 |
6 | 242442342201535 |
7 | 21351665034263 |
oct | 3102150237743 |
9 | 676053442815 |
10 | 215044145123 |
11 | 832218a5095 |
12 | 35815a232ab |
13 | 173810536b2 |
14 | a5a01177a3 |
15 | 58d90a8b18 |
hex | 3211a13fe3 |
215044145123 has 2 divisors, whose sum is σ = 215044145124. Its totient is φ = 215044145122.
The previous prime is 215044145039. The next prime is 215044145131. The reversal of 215044145123 is 321541440512.
215044145123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 215044145123 - 212 = 215044141027 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 215044145123.
It is not a weakly prime, because it can be changed into another prime (215044144123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107522072561 + 107522072562.
It is an arithmetic number, because the mean of its divisors is an integer number (107522072562).
Almost surely, 2215044145123 is an apocalyptic number.
215044145123 is a deficient number, since it is larger than the sum of its proper divisors (1).
215044145123 is an equidigital number, since it uses as much as digits as its factorization.
215044145123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19200, while the sum is 32.
Adding to 215044145123 its reverse (321541440512), we get a palindrome (536585585635).
The spelling of 215044145123 in words is "two hundred fifteen billion, forty-four million, one hundred forty-five thousand, one hundred twenty-three".
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