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215044145131 is a prime number
BaseRepresentation
bin1100100001000110100…
…0010011111111101011
3202120001210111102220211
43020101220103333223
512010402300121011
6242442342201551
721351665034304
oct3102150237753
9676053442824
10215044145131
11832218a50a2
1235815a232b7
13173810536ba
14a5a01177ab
1558d90a8b21
hex3211a13feb

215044145131 has 2 divisors, whose sum is σ = 215044145132. Its totient is φ = 215044145130.

The previous prime is 215044145123. The next prime is 215044145209. The reversal of 215044145131 is 131541440512.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 215044145131 - 23 = 215044145123 is a prime.

It is a super-2 number, since 2×2150441451312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 215044145093 and 215044145102.

It is not a weakly prime, because it can be changed into another prime (215044145431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107522072565 + 107522072566.

It is an arithmetic number, because the mean of its divisors is an integer number (107522072566).

Almost surely, 2215044145131 is an apocalyptic number.

215044145131 is a deficient number, since it is larger than the sum of its proper divisors (1).

215044145131 is an equidigital number, since it uses as much as digits as its factorization.

215044145131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 215044145131 its reverse (131541440512), we get a palindrome (346585585643).

The spelling of 215044145131 in words is "two hundred fifteen billion, forty-four million, one hundred forty-five thousand, one hundred thirty-one".