Base | Representation |
---|---|
bin | 1100100001000110100… |
… | …0010011111111101011 |
3 | 202120001210111102220211 |
4 | 3020101220103333223 |
5 | 12010402300121011 |
6 | 242442342201551 |
7 | 21351665034304 |
oct | 3102150237753 |
9 | 676053442824 |
10 | 215044145131 |
11 | 832218a50a2 |
12 | 35815a232b7 |
13 | 173810536ba |
14 | a5a01177ab |
15 | 58d90a8b21 |
hex | 3211a13feb |
215044145131 has 2 divisors, whose sum is σ = 215044145132. Its totient is φ = 215044145130.
The previous prime is 215044145123. The next prime is 215044145209. The reversal of 215044145131 is 131541440512.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 215044145131 - 23 = 215044145123 is a prime.
It is a super-2 number, since 2×2150441451312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 215044145093 and 215044145102.
It is not a weakly prime, because it can be changed into another prime (215044145431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107522072565 + 107522072566.
It is an arithmetic number, because the mean of its divisors is an integer number (107522072566).
Almost surely, 2215044145131 is an apocalyptic number.
215044145131 is a deficient number, since it is larger than the sum of its proper divisors (1).
215044145131 is an equidigital number, since it uses as much as digits as its factorization.
215044145131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 215044145131 its reverse (131541440512), we get a palindrome (346585585643).
The spelling of 215044145131 in words is "two hundred fifteen billion, forty-four million, one hundred forty-five thousand, one hundred thirty-one".
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