Base | Representation |
---|---|
bin | 11111010010111100110… |
… | …110010100111010111001 |
3 | 21121121012122011201000201 |
4 | 133102330312110322321 |
5 | 240214013403143243 |
6 | 4323555040202201 |
7 | 311244106266454 |
oct | 37227466247271 |
9 | 7547178151021 |
10 | 2150652006073 |
11 | 75a0a4a9882a |
12 | 2a8989009361 |
13 | 127a61c1a92c |
14 | 76140a8449b |
15 | 3ae23e4e04d |
hex | 1f4bcd94eb9 |
2150652006073 has 2 divisors, whose sum is σ = 2150652006074. Its totient is φ = 2150652006072.
The previous prime is 2150652006047. The next prime is 2150652006079. The reversal of 2150652006073 is 3706002560512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1438675504704 + 711976501369 = 1199448^2 + 843787^2 .
It is a cyclic number.
It is not a de Polignac number, because 2150652006073 - 213 = 2150651997881 is a prime.
It is not a weakly prime, because it can be changed into another prime (2150652006079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075326003036 + 1075326003037.
It is an arithmetic number, because the mean of its divisors is an integer number (1075326003037).
Almost surely, 22150652006073 is an apocalyptic number.
It is an amenable number.
2150652006073 is a deficient number, since it is larger than the sum of its proper divisors (1).
2150652006073 is an equidigital number, since it uses as much as digits as its factorization.
2150652006073 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 75600, while the sum is 37.
Adding to 2150652006073 its reverse (3706002560512), we get a palindrome (5856654566585).
The spelling of 2150652006073 in words is "two trillion, one hundred fifty billion, six hundred fifty-two million, six thousand, seventy-three".
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