Base | Representation |
---|---|
bin | 11111010010111100110… |
… | …110010100111010011111 |
3 | 21121121012122011200222202 |
4 | 133102330312110322133 |
5 | 240214013403143142 |
6 | 4323555040202115 |
7 | 311244106266416 |
oct | 37227466247237 |
9 | 7547178150882 |
10 | 2150652006047 |
11 | 75a0a4a98806 |
12 | 2a898900933b |
13 | 127a61c1a90c |
14 | 76140a8447d |
15 | 3ae23e4e032 |
hex | 1f4bcd94e9f |
2150652006047 has 2 divisors, whose sum is σ = 2150652006048. Its totient is φ = 2150652006046.
The previous prime is 2150652006031. The next prime is 2150652006073. The reversal of 2150652006047 is 7406002560512.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2150652006047 - 24 = 2150652006031 is a prime.
It is a super-2 number, since 2×21506520060472 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2150652006047.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2150652006247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075326003023 + 1075326003024.
It is an arithmetic number, because the mean of its divisors is an integer number (1075326003024).
Almost surely, 22150652006047 is an apocalyptic number.
2150652006047 is a deficient number, since it is larger than the sum of its proper divisors (1).
2150652006047 is an equidigital number, since it uses as much as digits as its factorization.
2150652006047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 38.
Adding to 2150652006047 its reverse (7406002560512), we get a palindrome (9556654566559).
The spelling of 2150652006047 in words is "two trillion, one hundred fifty billion, six hundred fifty-two million, six thousand, forty-seven".
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