Base | Representation |
---|---|
bin | 11111010010111100110… |
… | …110110001000000101011 |
3 | 21121121012122101112212010 |
4 | 133102330312301000223 |
5 | 240214013420334011 |
6 | 4323555042451003 |
7 | 311244110256063 |
oct | 37227466610053 |
9 | 7547178345763 |
10 | 2150652121131 |
11 | 75a0a5067218 |
12 | 2a8989063a63 |
13 | 127a61c5b107 |
14 | 76140ab43a3 |
15 | 3ae23e731a6 |
hex | 1f4bcdb102b |
2150652121131 has 8 divisors (see below), whose sum is σ = 2867548585104. Its totient is φ = 1433761868960.
The previous prime is 2150652121061. The next prime is 2150652121181. The reversal of 2150652121131 is 1311212560512.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2150652121131 - 27 = 2150652121003 is a prime.
It is a super-2 number, since 2×21506521211312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2150652121181) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 674040 + ... + 2180741.
It is an arithmetic number, because the mean of its divisors is an integer number (358443573138).
Almost surely, 22150652121131 is an apocalyptic number.
2150652121131 is a deficient number, since it is larger than the sum of its proper divisors (716896463973).
2150652121131 is a wasteful number, since it uses less digits than its factorization.
2150652121131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3105901.
The product of its (nonzero) digits is 3600, while the sum is 30.
Adding to 2150652121131 its reverse (1311212560512), we get a palindrome (3461864681643).
The spelling of 2150652121131 in words is "two trillion, one hundred fifty billion, six hundred fifty-two million, one hundred twenty-one thousand, one hundred thirty-one".
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