Base | Representation |
---|---|
bin | 1001110001111100111001… |
… | …10011100100010001111001 |
3 | 2211011002200212220122011012 |
4 | 10320332130303210101321 |
5 | 10304334411143432323 |
6 | 113424231313043305 |
7 | 4346603456513003 |
oct | 470763463442171 |
9 | 84132625818135 |
10 | 21507532014713 |
11 | 6942325138578 |
12 | 24b4378b56535 |
13 | c001c7cb7384 |
14 | 544d81d71373 |
15 | 2746d85d8678 |
hex | 138f9cce4479 |
21507532014713 has 2 divisors, whose sum is σ = 21507532014714. Its totient is φ = 21507532014712.
The previous prime is 21507532014673. The next prime is 21507532014763. The reversal of 21507532014713 is 31741023570512.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20051158533904 + 1456373480809 = 4477852^2 + 1206803^2 .
It is a cyclic number.
It is not a de Polignac number, because 21507532014713 - 26 = 21507532014649 is a prime.
It is not a weakly prime, because it can be changed into another prime (21507532014763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10753766007356 + 10753766007357.
It is an arithmetic number, because the mean of its divisors is an integer number (10753766007357).
Almost surely, 221507532014713 is an apocalyptic number.
It is an amenable number.
21507532014713 is a deficient number, since it is larger than the sum of its proper divisors (1).
21507532014713 is an equidigital number, since it uses as much as digits as its factorization.
21507532014713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 176400, while the sum is 41.
The spelling of 21507532014713 in words is "twenty-one trillion, five hundred seven billion, five hundred thirty-two million, fourteen thousand, seven hundred thirteen".
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