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2151001500121 = 6383473369643
BaseRepresentation
bin11111010011010001101…
…011100010100111011001
321121122002222210211201201
4133103101223202213121
5240220222341000441
64324053443114201
7311255552035525
oct37232153424731
97548088724651
102151001500121
1175a2642a7891
122a8a66072961
13127ab9457746
147617525cd85
153ae44987c31
hex1f4d1ae29d9

2151001500121 has 4 divisors (see below), whose sum is σ = 2151005508112. Its totient is φ = 2150997492132.

The previous prime is 2151001500113. The next prime is 2151001500173. The reversal of 2151001500121 is 1210051001512.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2151001500121 - 23 = 2151001500113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2151001503121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1046475 + ... + 2323168.

It is an arithmetic number, because the mean of its divisors is an integer number (537751377028).

Almost surely, 22151001500121 is an apocalyptic number.

It is an amenable number.

2151001500121 is a deficient number, since it is larger than the sum of its proper divisors (4007991).

2151001500121 is an equidigital number, since it uses as much as digits as its factorization.

2151001500121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4007990.

The product of its (nonzero) digits is 100, while the sum is 19.

Adding to 2151001500121 its reverse (1210051001512), we get a palindrome (3361052501633).

The spelling of 2151001500121 in words is "two trillion, one hundred fifty-one billion, one million, five hundred thousand, one hundred twenty-one".

Divisors: 1 638347 3369643 2151001500121