Base | Representation |
---|---|
bin | 11111010011010001111… |
… | …001000000101110010001 |
3 | 21121122010020110020121121 |
4 | 133103101321000232101 |
5 | 240220224242000223 |
6 | 4324054050522241 |
7 | 311255624043535 |
oct | 37232171005621 |
9 | 7548106406547 |
10 | 2151005031313 |
11 | 75a266299926 |
12 | 2a8a67296381 |
13 | 127aba0c2ac8 |
14 | 761758dbbc5 |
15 | 3ae44e3415d |
hex | 1f4d1e40b91 |
2151005031313 has 2 divisors, whose sum is σ = 2151005031314. Its totient is φ = 2151005031312.
The previous prime is 2151005031311. The next prime is 2151005031347. The reversal of 2151005031313 is 3131305001512.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1274072047504 + 876932983809 = 1128748^2 + 936447^2 .
It is a cyclic number.
It is not a de Polignac number, because 2151005031313 - 21 = 2151005031311 is a prime.
It is a super-2 number, since 2×21510050313132 (a number of 25 digits) contains 22 as substring.
Together with 2151005031311, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (2151005031311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075502515656 + 1075502515657.
It is an arithmetic number, because the mean of its divisors is an integer number (1075502515657).
Almost surely, 22151005031313 is an apocalyptic number.
It is an amenable number.
2151005031313 is a deficient number, since it is larger than the sum of its proper divisors (1).
2151005031313 is an equidigital number, since it uses as much as digits as its factorization.
2151005031313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1350, while the sum is 25.
The spelling of 2151005031313 in words is "two trillion, one hundred fifty-one billion, five million, thirty-one thousand, three hundred thirteen".
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