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21510220314113 is a prime number
BaseRepresentation
bin1001110010000001111010…
…00010100111011000000001
32211011100122020102101122122
410321000331002213120001
510304410412400022423
6113425354144414025
74350030211624406
oct471007502473001
984140566371578
1021510220314113
116943484662713
1224b49a9317315
13c00535c3518b
14545158dda2ad
152747e460b8c8
hex13903d0a7601

21510220314113 has 2 divisors, whose sum is σ = 21510220314114. Its totient is φ = 21510220314112.

The previous prime is 21510220314109. The next prime is 21510220314131. The reversal of 21510220314113 is 31141302201512.

Together with next prime (21510220314131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21409434383089 + 100785931024 = 4627033^2 + 317468^2 .

It is a cyclic number.

It is not a de Polignac number, because 21510220314113 - 22 = 21510220314109 is a prime.

It is not a weakly prime, because it can be changed into another prime (21510220314133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10755110157056 + 10755110157057.

It is an arithmetic number, because the mean of its divisors is an integer number (10755110157057).

Almost surely, 221510220314113 is an apocalyptic number.

It is an amenable number.

21510220314113 is a deficient number, since it is larger than the sum of its proper divisors (1).

21510220314113 is an equidigital number, since it uses as much as digits as its factorization.

21510220314113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 21510220314113 its reverse (31141302201512), we get a palindrome (52651522515625).

The spelling of 21510220314113 in words is "twenty-one trillion, five hundred ten billion, two hundred twenty million, three hundred fourteen thousand, one hundred thirteen".