21510220314131 has 2 divisors, whose sum is σ = 21510220314132. Its totient is φ = 21510220314130.

The previous prime is 21510220314113. The next prime is 21510220314133. The reversal of 21510220314131 is 13141302201512.

Together with previous prime (21510220314113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21510220314131 - 2²² = 21510216119827 is a prime.

It is a super-3 number, since 3×21510220314131³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 21510220314133, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21510220314131.

It is not a weakly prime, because it can be changed into another prime (21510220314133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10755110157065 + 10755110157066.

It is an arithmetic number, because the mean of its divisors is an integer number (10755110157066).

Almost surely, 2^{21510220314131} is an apocalyptic number.

21510220314131 is a deficient number, since it is larger than the sum of its proper divisors (1).

21510220314131 is an equidigital number, since it uses as much as digits as its factorization.

21510220314131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 21510220314131 its reverse (13141302201512), we get a palindrome (34651522515643).

The spelling of 21510220314131 in words is "twenty-one trillion, five hundred ten billion, two hundred twenty million, three hundred fourteen thousand, one hundred thirty-one".