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2151155565401 is a prime number
BaseRepresentation
bin11111010011011010110…
…111010000001101011001
321121122111201201011120012
4133103122313100031121
5240221031311043101
64324121025211305
7311262432416453
oct37233267201531
97548451634505
102151155565401
1175a333266367
122a8aa9790b35
13127b1234ab2b
147618b8c52d3
153ae5326bbbb
hex1f4dadd0359

2151155565401 has 2 divisors, whose sum is σ = 2151155565402. Its totient is φ = 2151155565400.

The previous prime is 2151155565379. The next prime is 2151155565413. The reversal of 2151155565401 is 1045655511512.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1741478761801 + 409676803600 = 1319651^2 + 640060^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2151155565401 is a prime.

It is not a weakly prime, because it can be changed into another prime (2151155565001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075577782700 + 1075577782701.

It is an arithmetic number, because the mean of its divisors is an integer number (1075577782701).

Almost surely, 22151155565401 is an apocalyptic number.

It is an amenable number.

2151155565401 is a deficient number, since it is larger than the sum of its proper divisors (1).

2151155565401 is an equidigital number, since it uses as much as digits as its factorization.

2151155565401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 150000, while the sum is 41.

The spelling of 2151155565401 in words is "two trillion, one hundred fifty-one billion, one hundred fifty-five million, five hundred sixty-five thousand, four hundred one".