Base | Representation |
---|---|
bin | 1001110010000110001101… |
… | …01110100110101101110111 |
3 | 2211011120121020010001222002 |
4 | 10321003012232212231313 |
5 | 10304430130230334333 |
6 | 113430415304125515 |
7 | 4350141361450202 |
oct | 471030656465567 |
9 | 84146536101862 |
10 | 21512530324343 |
11 | 694445a5a0583 |
12 | 24b5332a6689b |
13 | c008136a3736 |
14 | 5452d7b12939 |
15 | 2748cc3090e8 |
hex | 1390c6ba6b77 |
21512530324343 has 2 divisors, whose sum is σ = 21512530324344. Its totient is φ = 21512530324342.
The previous prime is 21512530324331. The next prime is 21512530324349. The reversal of 21512530324343 is 34342303521512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21512530324343 - 244 = 3920344279927 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21512530324297 and 21512530324306.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21512530324349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10756265162171 + 10756265162172.
It is an arithmetic number, because the mean of its divisors is an integer number (10756265162172).
Almost surely, 221512530324343 is an apocalyptic number.
21512530324343 is a deficient number, since it is larger than the sum of its proper divisors (1).
21512530324343 is an equidigital number, since it uses as much as digits as its factorization.
21512530324343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 21512530324343 its reverse (34342303521512), we get a palindrome (55854833845855).
The spelling of 21512530324343 in words is "twenty-one trillion, five hundred twelve billion, five hundred thirty million, three hundred twenty-four thousand, three hundred forty-three".
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