Base | Representation |
---|---|
bin | 11111010011100010010… |
… | …110111001011100010111 |
3 | 21121122211111022012202021 |
4 | 133103202112321130113 |
5 | 240221311003120041 |
6 | 4324141320154011 |
7 | 311265520230364 |
oct | 37234226713427 |
9 | 7548744265667 |
10 | 2151281301271 |
11 | 75a398235603 |
12 | 2a8b23908907 |
13 | 127b3240275b |
14 | 761a049546b |
15 | 3ae5e306cd1 |
hex | 1f4e25b9717 |
2151281301271 has 2 divisors, whose sum is σ = 2151281301272. Its totient is φ = 2151281301270.
The previous prime is 2151281301241. The next prime is 2151281301359. The reversal of 2151281301271 is 1721031821512.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2151281301271 - 213 = 2151281293079 is a prime.
It is a super-2 number, since 2×21512813012712 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2151281301241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075640650635 + 1075640650636.
It is an arithmetic number, because the mean of its divisors is an integer number (1075640650636).
Almost surely, 22151281301271 is an apocalyptic number.
2151281301271 is a deficient number, since it is larger than the sum of its proper divisors (1).
2151281301271 is an equidigital number, since it uses as much as digits as its factorization.
2151281301271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 34.
The spelling of 2151281301271 in words is "two trillion, one hundred fifty-one billion, two hundred eighty-one million, three hundred one thousand, two hundred seventy-one".
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