Base | Representation |
---|---|
bin | 11111010011100110101… |
… | …101111001100101101100 |
3 | 21121200000120221001021201 |
4 | 133103212231321211230 |
5 | 240221433214040134 |
6 | 4324152451535244 |
7 | 311300366006065 |
oct | 37234655714554 |
9 | 7550016831251 |
10 | 2151354440044 |
11 | 75a42554a877 |
12 | 2a8b442ba524 |
13 | 127b445ccb34 |
14 | 761aa09356c |
15 | 3ae65952914 |
hex | 1f4e6b7996c |
2151354440044 has 12 divisors (see below), whose sum is σ = 3886317698368. Its totient is φ = 1040977954800.
The previous prime is 2151354440023. The next prime is 2151354440149. The reversal of 2151354440044 is 4400444531512.
It is a junction number, because it is equal to n+sod(n) for n = 2151354439985 and 2151354440012.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8674816167 + ... + 8674816414.
Almost surely, 22151354440044 is an apocalyptic number.
It is an amenable number.
2151354440044 is a deficient number, since it is larger than the sum of its proper divisors (1734963258324).
2151354440044 is a wasteful number, since it uses less digits than its factorization.
2151354440044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17349632616 (or 17349632614 counting only the distinct ones).
The product of its (nonzero) digits is 153600, while the sum is 37.
Adding to 2151354440044 its reverse (4400444531512), we get a palindrome (6551798971556).
The spelling of 2151354440044 in words is "two trillion, one hundred fifty-one billion, three hundred fifty-four million, four hundred forty thousand, forty-four".
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