Base | Representation |
---|---|
bin | 11111010011100110101… |
… | …101111001100111010101 |
3 | 21121200000120221001102121 |
4 | 133103212231321213111 |
5 | 240221433214041044 |
6 | 4324152451535541 |
7 | 311300366006305 |
oct | 37234655714725 |
9 | 7550016831377 |
10 | 2151354440149 |
11 | 75a42554a962 |
12 | 2a8b442ba5b1 |
13 | 127b445ccbb5 |
14 | 761aa093605 |
15 | 3ae65952984 |
hex | 1f4e6b799d5 |
2151354440149 has 2 divisors, whose sum is σ = 2151354440150. Its totient is φ = 2151354440148.
The previous prime is 2151354440023. The next prime is 2151354440153. The reversal of 2151354440149 is 9410444531512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1526966847025 + 624387593124 = 1235705^2 + 790182^2 .
It is a cyclic number.
It is not a de Polignac number, because 2151354440149 - 213 = 2151354431957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2151354440749) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075677220074 + 1075677220075.
It is an arithmetic number, because the mean of its divisors is an integer number (1075677220075).
Almost surely, 22151354440149 is an apocalyptic number.
It is an amenable number.
2151354440149 is a deficient number, since it is larger than the sum of its proper divisors (1).
2151354440149 is an equidigital number, since it uses as much as digits as its factorization.
2151354440149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 345600, while the sum is 43.
The spelling of 2151354440149 in words is "two trillion, one hundred fifty-one billion, three hundred fifty-four million, four hundred forty thousand, one hundred forty-nine".
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