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21514422105031 is a prime number
BaseRepresentation
bin1001110010001001101110…
…11111001011001111000111
32211011202111001211111012111
410321010313133023033013
510304443014024330111
6113431331123401451
74350236302354612
oct471046737131707
984152431744174
1021514422105031
116945240442399
1224b5780523287
13c00a555ba0ab
1454543707b179
1527498d441a21
hex1391377cb3c7

21514422105031 has 2 divisors, whose sum is σ = 21514422105032. Its totient is φ = 21514422105030.

The previous prime is 21514422104999. The next prime is 21514422105061. The reversal of 21514422105031 is 13050122441512.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21514422105031 - 25 = 21514422104999 is a prime.

It is a super-2 number, since 2×215144221050312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21514422104984 and 21514422105002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21514422105061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10757211052515 + 10757211052516.

It is an arithmetic number, because the mean of its divisors is an integer number (10757211052516).

Almost surely, 221514422105031 is an apocalyptic number.

21514422105031 is a deficient number, since it is larger than the sum of its proper divisors (1).

21514422105031 is an equidigital number, since it uses as much as digits as its factorization.

21514422105031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 21514422105031 its reverse (13050122441512), we get a palindrome (34564544546543).

The spelling of 21514422105031 in words is "twenty-one trillion, five hundred fourteen billion, four hundred twenty-two million, one hundred five thousand, thirty-one".