Base | Representation |
---|---|
bin | 11111010011101101111… |
… | …100101000001011001111 |
3 | 21121200100001011210110012 |
4 | 133103231330220023033 |
5 | 240222210242211031 |
6 | 4324212503503435 |
7 | 311303401030244 |
oct | 37235574501317 |
9 | 7550301153405 |
10 | 2151475741391 |
11 | 75a487a70319 |
12 | 2a8b78a57b7b |
13 | 127b63791192 |
14 | 761bc22b5cb |
15 | 3ae71413b2b |
hex | 1f4edf282cf |
2151475741391 has 2 divisors, whose sum is σ = 2151475741392. Its totient is φ = 2151475741390.
The previous prime is 2151475741369. The next prime is 2151475741433. The reversal of 2151475741391 is 1931475741512.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2151475741391 - 230 = 2150401999567 is a prime.
It is a super-2 number, since 2×21514757413912 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2151475741301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075737870695 + 1075737870696.
It is an arithmetic number, because the mean of its divisors is an integer number (1075737870696).
Almost surely, 22151475741391 is an apocalyptic number.
2151475741391 is a deficient number, since it is larger than the sum of its proper divisors (1).
2151475741391 is an equidigital number, since it uses as much as digits as its factorization.
2151475741391 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1058400, while the sum is 50.
The spelling of 2151475741391 in words is "two trillion, one hundred fifty-one billion, four hundred seventy-five million, seven hundred forty-one thousand, three hundred ninety-one".
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