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2152013141 = 5936474799
BaseRepresentation
bin1000000001000101…
…0001110101010101
312112222101121001102
42000101101311111
513401403410031
6553313035445
7104220544535
oct20021216525
95488347042
102152013141
11a04834363
12500855b85
13283acc675
14165b494c5
15c8ddd7cb
hex80451d55

2152013141 has 4 divisors (see below), whose sum is σ = 2188488000. Its totient is φ = 2115538284.

The previous prime is 2152013137. The next prime is 2152013159. The reversal of 2152013141 is 1413102512.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2152013141 - 22 = 2152013137 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2152013341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18237341 + ... + 18237458.

It is an arithmetic number, because the mean of its divisors is an integer number (547122000).

Almost surely, 22152013141 is an apocalyptic number.

It is an amenable number.

2152013141 is a deficient number, since it is larger than the sum of its proper divisors (36474859).

2152013141 is an equidigital number, since it uses as much as digits as its factorization.

2152013141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36474858.

The product of its (nonzero) digits is 240, while the sum is 20.

The square root of 2152013141 is about 46389.7956559414. The cubic root of 2152013141 is about 1291.0655901035.

Adding to 2152013141 its reverse (1413102512), we get a palindrome (3565115653).

The spelling of 2152013141 in words is "two billion, one hundred fifty-two million, thirteen thousand, one hundred forty-one".

Divisors: 1 59 36474799 2152013141