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21530354471 = 136115819511
BaseRepresentation
bin10100000011010011…
…110010001100100111
32001120111011022220222
4110003103302030213
5323043232320341
613520234114555
71361353664513
oct240323621447
961514138828
1021530354471
119149361a8a
12420a57ba5b
132051767322
14108364b143
158602ae44b
hex5034f2327

21530354471 has 4 divisors (see below), whose sum is σ = 21546175344. Its totient is φ = 21514533600.

The previous prime is 21530354467. The next prime is 21530354509. The reversal of 21530354471 is 17445303512.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21530354471 - 22 = 21530354467 is a prime.

It is a super-3 number, since 3×215303544713 (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21530359471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7908395 + ... + 7911116.

It is an arithmetic number, because the mean of its divisors is an integer number (5386543836).

Almost surely, 221530354471 is an apocalyptic number.

21530354471 is a deficient number, since it is larger than the sum of its proper divisors (15820873).

21530354471 is a wasteful number, since it uses less digits than its factorization.

21530354471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15820872.

The product of its (nonzero) digits is 50400, while the sum is 35.

Adding to 21530354471 its reverse (17445303512), we get a palindrome (38975657983).

The spelling of 21530354471 in words is "twenty-one billion, five hundred thirty million, three hundred fifty-four thousand, four hundred seventy-one".

Divisors: 1 1361 15819511 21530354471